Wednesday, 27 November 2019
Wednesday, 20 November 2019
Textbooks and Mathematics
The modality of the linguistics is really important for the textbooks to be useful for the readers. It is interesting to notice that the use of the first-person pronouns( I and We) in the math textbooks helps the readers to get involved in the textbooks and make better connections. The absence of the first-person pronouns makes the textbook really dull and it also distances the reader from what the author wants to explain. Moreover, the use of second-person pronouns( you) connects the reader directly to mathematics. I remember, during my high school days, I use to connect more to the questions which involved first and second-person pronouns. It helped me to imagine the experience what the authors want to interpret. In addition to this, the use of the graphics and the photographs also make a huge difference in the student's understanding. Although I agree with the author of the article that graphics are more helpful as it generalizes the domain whereas the photograph talks about that particular person. For instance, the example of the hand doing mathematics in the article, lets the readers imagine their own hand doing mathematics and helps them to have a better understanding and experience. I remember my mathematics textbooks in my high school and college was all about numbers and variables which would not make sense to any layman reading the textbook. There were no pictures for the reader to make connections to the real world. Therefore, only the students who loved numbers or were interested in math would excel in math, and the textbooks were not good enough to develop anyone's interest.
According to me, the use of textbooks should not be ruled out completely, some good points can be incorporated by the teachers from textbooks for making their teaching and learning better. Especially, the textbook questions can be used to do more practice. I believe a teacher can play an important role in the interpretation of the information written in the textbook, even if the textbook is not good enough for the student readers. As per my recent experience, while making the unit plan for science, I found BC connection 9 textbook really helpful and I was amazed to see how beautifully the author made connections between the science concepts and the outer world.
According to me, the use of textbooks should not be ruled out completely, some good points can be incorporated by the teachers from textbooks for making their teaching and learning better. Especially, the textbook questions can be used to do more practice. I believe a teacher can play an important role in the interpretation of the information written in the textbook, even if the textbook is not good enough for the student readers. As per my recent experience, while making the unit plan for science, I found BC connection 9 textbook really helpful and I was amazed to see how beautifully the author made connections between the science concepts and the outer world.
Wednesday, 13 November 2019
Scales Problem
The first weight which I think the vendor should have is 1 g weight. Then I was in a dilemma should I opt for 3 g or 2 g. Initially, I chose 2g and I was able to get a maximum of 3 g but if I chose 3g then 3-1 will give me 2 and 3+ 1 will give 4g. So, till now I thought 1g and 3g should be fine to weigh the herbs till 4g. Now in order to weigh 5 g next highest weigh should be 9 g since, 9-3-1 = 5 g, I tried with 8g but Using 1, 3 and 8. I was able to get to the maximum at 12 g in comparison to 9,1,3 which leads to 13. For instance, I chose 1,3,8 then the highest weight I figured out was 25g since 25-8-3-1= 13g, But using 1,3,8,25 the maximum I was able to reach was 37g( 1+3+8+25). Therefore, I figured out I should choose 9 instead of 8. Since 1, 3, 9 covered all the weighs from 5g to 13g.
9-3-1=5
9-3=6
9-3+1=7
9-1=8
9+1=10
9+3-1=11
9+3=12
9+3+1=13
The weight should be 27g since 1+3+9+x= 40, so x=27g.
Moreover, using 1,3,9,27 we can have the weighs after 13g.
27-9-3-1=14 27-9+3=21 27+3-1=29 27+9=36
27-9-3=15 27-9+3+1=22 27+3=30 27+9+1=37
27-9-3+1=16 27-3-1=23 27+3+1=31 27+9+3-1=38
27-9-1=17 27-3=24 27+9-3-1=32 27+9+3=39
27-9=18 27-3+1=25 27+9-3=33 27+9+1+3=40
27-9+1=19 27-1=26 27+9-3+1=34
27-9+3-1=20 27+1=28 27+9-1=35
9-3-1=5
9-3=6
9-3+1=7
9-1=8
9+1=10
9+3-1=11
9+3=12
9+3+1=13
The weight should be 27g since 1+3+9+x= 40, so x=27g.
Moreover, using 1,3,9,27 we can have the weighs after 13g.
27-9-3-1=14 27-9+3=21 27+3-1=29 27+9=36
27-9-3=15 27-9+3+1=22 27+3=30 27+9+1=37
27-9-3+1=16 27-3-1=23 27+3+1=31 27+9+3-1=38
27-9-1=17 27-3=24 27+9-3-1=32 27+9+3=39
27-9=18 27-3+1=25 27+9-3=33 27+9+1+3=40
27-9+1=19 27-1=26 27+9-3+1=34
27-9+3-1=20 27+1=28 27+9-1=35
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